X≥4ft 6 in an inequality represents this situation better than an equation because there isnt really a mathematical process required in finding a certain hight limit
<h3>
▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
We know that, Two angles are said to be complementary, if the sum of their measures is 90°.
<u>According to the Question</u>,
⇒ ∠ABD + ∠DBC = 90°
⇒ (2x + 30)° + (3x + 20)° = 90°
⇒ 2x + 30° + 3x + 20° = 90°
⇒ 5x + 50° = 90°
⇒ 5x = 90° - 50°
⇒ 5x = 40°
⇒ x = 40°/5
⇒ x = 8
<u>So</u>, <u>t</u><u>he measure of each angle will be</u>,
⇒ ∠ABD = (2x + 30)°
= 2 × 8 + 30°
= 16 + 30°
= 46°
⇒ ∠DBC = (3x + 20)°
= 3 × 8 + 30°
= 24 + 30°
<h3>
= 54° ▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
Rearrange the equation into slope intercept form
7x+3y=18
3y=-7x+18
y=-7x/3+18/3 so the slope of the reference line is -7/3
To be perpendicular to this line the slope must be the negative reciprocal of this...mathematically m1*m2=-1. So the slope of our perpendicular line is:
-7m/3=-1
-7m=-3
m=3/7 so our line so far is:
y=3x/7+b, using point (6,8) we can solve for b, the y-intercept
8=3(6)/7+b
8=18/7+b
56/7-18/7=b
38/7=b so our line is:
y=3x/7+38/7 or if you prefer
y=(3x+38)/7