Look at deonomators
assuming that the deonomenators are 5x+15y and 2x+6y
find their LCM
factor
5x+15y=5(x+3y)
2x+6y=2(x+3y)
LCM=10(x+3y)=10x+30y
multiply 2/(5x+15y) by 2/2=4/(10x+30y)
multiply 1/(2x+6y) by 5/5=5/(10x+30y)
if we add them
9/(10x+30y)
58^(1/2) is √58 if that is what you meant
4x-8=2x+14
subtract 2x on both sides and add 8 on both sides so x=11
The answer to this equation would be k=2
Answer:
x∈(0,1], x is natural number.
