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Xelga [282]
3 years ago
5

If point A is located at (0,-8) and B is located at (4,-5) what is the distance between them

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{0}~,~\stackrel{y_1}{-8})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4-0]^2+[-5-(-8)]^2}\implies AB=\sqrt{(4-0)^2+(-5+8)^2} \\\\\\ AB=\sqrt{4^2+3^2}\implies AB=\sqrt{25}\implies AB=5

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Find the shaded region of the figure below​
lilavasa [31]

Answer:

-x³ + 3x² - 14x + 12

Step-by-step explanation:

Area of outer rectangle = (x² + 3x - 4) * (2x - 3)

      = (x² + 3x - 4) * 2x  + (x² + 3x - 4) * (-3)

     =x²*2x + 3x *2x - 4*2x  + x² *(-3) + 3x *(-3)  - 4*(-3)

     =2x³ + 6x² - 8x - 3x² - 9x + 12

    = 2x³ + <u>6x² - 3x²</u>   <u>- 8x - 9x</u> + 12     {Combine like terms}

    = 2x³ + 3x² - 17x + 12

Area of inner rectangle = (x² - 1)* 3x

                                       = x² *3x - 1*3x

                                       = 3x³ - 3x

Area of shaded region = area of outer rectangle - area of inner rectangle

         = 2x³ + 3x² - 17x + 12 - (3x³ - 3x)

         = 2x³ + 3x² - 17x + 12 -3x³ + 3x

        = 2x³ - 3x³ + 3x² - 17x + 3x + 12

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VashaNatasha [74]
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Read 2 more answers
Solve for a. Show your work (ALL steps must be shown): -2(a-3)=12
irga5000 [103]

Answer

a= -6

Step-by-step explanation:

-2(a-3)=12

1.) -2(a)= -2a

2) -2(-3)= 6

3)  -2a+6=12

          -6    -6

4) -2a/-2 = 12/-2

a = -6

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