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2 years ago

NEED HELP ASAPPP PLS HELPP question 3 !!

Mathematics

1 answer:

Serhud [2]2 years ago

7 0

Answer: It might be C

Step-by-step explanation:

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They made $126.75 on Monday

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The Candy Store is having a 30% off sale. Emma is buying candy worth $7.50. Who much will the Candy worth after the discount? Pl

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3 years ago

Read 2 more answers

A particle moves with velocity vector

asambeis [7]

Answer:

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}$

Step-by-step explanation:

We are given that velocity vector of a particle

$\vec{v(t)}=t\hat{i}-2\hat{j}+t^2\hat{k}$

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle at time t.

We know that

Velocity = $\frac{Displacement }{time}=\frac{ds}{dt}$

Therefore, $\vec{v}=\frac{\vec{ds}}{dt}$

$\int{ds}=\int (t\hat{i}-2\hat{j}+t^2\hat{k})dt$

Integrate on both sides then we get

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C$

$\int x^n dx=\frac{x^{n+1}}{n+1}+C$

Substitute the value of point at time t=0 then we get

C= $-\hat{j}+\hat{k}$

Substitute the value of C then we get

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}-\hat{j}+\hat{k}$

Therefore, the position of particle at time t

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}$

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3 years ago

A French class has a total of

balu736 [363]

Their are 34 females in the class.

If 42 is the total amount of French students; subtract the amount of males(8) from the whole class to receive how many females their are in the class. Which is 34.

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3 years ago