Question

Solve the equations for x: x^2+nx-mx-nm=0

Answer 1

Answer:

x =  [(m - n +/-√ (n^2 + m^2 + 2nm)]/2.

Step-by-step explanation:

x^2+nx-mx-nm=0

x^2 + (n - m)x - nm = 0

Using the quadratic formula:

x = [-(n - m) +/- √((n - m)^2 - 4*-nm)) / 2

= [(m - n +/- √ (n^2 + m^2 - 2nm + 4nm)]/2

=   [(m - n +/-√ (n^2 + m^2 + 2nm)]/2