Please help!!!! the question is in screenshot

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

$-\cos nw_0t$

Step-by-step explanation:

We can use the double angle identity for sine.

$\sin (A+B)=\sin A \cos B+\sin B\cos A$

The given expresion is

$\sin (nw_0t-90)$

We apply the identity to get:

$\sin (nw_0t-90)=\sin nw_0t \cos 90-\cos nw_0t \sin 90$

We simplify to obtain;

$\sin (nw_0t-90)=\sin nw_0t (0)-\cos nw_0t (1)$

This simplifies to:

$\sin (nw_0t-90)=-\cos nw_0t$ The correct answer is D

You might be interested in

A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from po

Ronch [10]

Directed numbers are numbers that have either a positive or negative sign, which can be shown on a number line. Therefore, point F is Fifteen-halves of line segment DE.

A number line is a system that can show the positions of positive or negative numbers. It has its ends ranging from negative infinity to positive infinity. Thus any directed number can be located on the line.

Directed numbers are numbers with either a negative or positive sign, which shows their direction with respect to the number line.

In the given question, the distance between points D and E is 9 units. So that dividing 9 units in the ratio of 5 to 6, we have;

$\frac{5}{6}$ x 9 = $\frac{45}{6}$

= $\frac{15}{2}$

Therefore, the location of point F, which partitions the directed line segment from d to E into a 5:6 ratio is $\frac{15}{2}$ . Thus the answer is Fifteen-halves.

For further clarifications on a number line, visit: brainly.com/question/23379455

#SPJ1