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3 years ago

Please help!!!! the question is in screenshot

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

$-\cos nw_0t$

Step-by-step explanation:

We can use the double angle identity for sine.

$\sin (A+B)=\sin A \cos B+\sin B\cos A$

The given expresion is

$\sin (nw_0t-90)$

We apply the identity to get:

$\sin (nw_0t-90)=\sin nw_0t \cos 90-\cos nw_0t \sin 90$

We simplify to obtain;

$\sin (nw_0t-90)=\sin nw_0t (0)-\cos nw_0t (1)$

This simplifies to:

$\sin (nw_0t-90)=-\cos nw_0t$ The correct answer is D

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Answer:

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Step-by-step explanation:

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_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.