<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>
<em>I think, to start out, we could set up the problem like so</em>
<em>15 + t ≥ 26</em>
<em>because t is not a set number. </em>
<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>
<em>t ≥ 11</em>
<em>So the resulting answer is t ≥ 11.</em>
<em />
<em>I hope that my interpretation helps.</em>
<em>-Toremi</em>
<em />
Answer: 20 km
Step-by-step explanation: Let's assume a trajectory of Ships A (which is moving at 6 km/h) and B (which is moving at 4 km/h)
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A 10 km B
And let's assume that who is going to the right is the positive.
Space (S) = S₀ + vt
For A, its space is SA = 0 + 6t
For B, its space is SB = 10 - 4t
They meet at SA = SB;
6t = 10 - 4t
6t + 4t = 10
10t = 10
t = 1h
If the bird is at 20 km/h and it will fly for 1h, it will travel 20 km
Answer:
x = 3
Step-by-step explanation:
j(x) = 4/5(-5) + 7
= -4 + 7
= 3
Answer:
See attachment
Step-by-step explanation:
The angles are congruent which means that the triangles are congruent.
WXY ~~ WZY