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slamgirl [31]
3 years ago
9

Find the inverse f(x)=(x-5)^2

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

f − 1 ( x ) = √ x + 5 , − √ x + 5

Step-by-step explanation:

To find the inverse, interchange the variables and solve for  y

LUCKY_DIMON [66]3 years ago
3 0

Answer:

f⁻¹(x) = ±√x + 5

Step-by-step explanation:

We have given  a function.

f(x) = (x-5)²

We have to find the inverse of given function.

Putting y = f(x) in given equation, we have

y = (x-5)²

Taking square root to both sides of above equation, we have

±√y  = x-5

x = ±√y + 5

Putting x = f⁻¹(y)  in above equation,we have

f⁻¹(y) = ±√y + 5

Replace y with x , we have

f⁻¹(x) = ±√x + 5 which is the answer.

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If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = \frac{y(b)-y(a)}{b-a}

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2.

(a)

(i) average speed = \frac{y(2)-y(1)}{2-1}

=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}

=50.42 m/s

(ii) average speed = \frac{y(1.5)-y(1)}{1.5-1}

=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}

=51.35m/s

(iii) average speed = \frac{y(1.1)-y(1)}{1.1-1}

=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}

=52.094m/s

(iv) average speed = \frac{y(1.01)-y(1)}{1.01-01}

=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}

=52.2614
m/s

(v) average speed = \frac{y(1.001)-y(1)}{1.001-01}

=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}

=52.27814
m/s

(b) y(1)=56(1)-1.86(1)^2

=56-1.86

= 54.14 m/s

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Answer:

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Step-by-step explanation:

Since P=36 and q=9, this looks like a ratio of 4:1. So if q=3, multiply that value by 4 to get your answer

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