Answer:
i don not know this. but I think
Step-by-step explanation:
Answer:
5.131 × 10¹⁴ Hz
Step-by-step explanation:
<u>Planck relation</u>
![\large\boxed{E = hf}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BE%20%3D%20hf%7D)
where:
- E = Energy of the photon (J).
- h = Planck's constant (J · s).
- f = frequency of light produced (Hz).
Given values:
- E = 3.4 × 10⁻¹⁹ J
- h = 6.626 × 10⁻³⁴ J · s
Substitute the given values into the formula and solve for f:
![\implies 3.4 \times 10^{-19}=(6.626 \times 10^{-34})f](https://tex.z-dn.net/?f=%5Cimplies%203.4%20%5Ctimes%2010%5E%7B-19%7D%3D%286.626%20%5Ctimes%2010%5E%7B-34%7D%29f)
![\implies f=\dfrac{3.4 \times 10^{-19}}{6.626 \times 10^{-34}}](https://tex.z-dn.net/?f=%5Cimplies%20f%3D%5Cdfrac%7B3.4%20%5Ctimes%2010%5E%7B-19%7D%7D%7B6.626%20%5Ctimes%2010%5E%7B-34%7D%7D)
![\implies f=\dfrac{3.4}{6.626} \times \dfrac{10^{-19}}{10^{-34}}](https://tex.z-dn.net/?f=%5Cimplies%20f%3D%5Cdfrac%7B3.4%7D%7B6.626%7D%20%5Ctimes%20%5Cdfrac%7B10%5E%7B-19%7D%7D%7B10%5E%7B-34%7D%7D)
![\implies f=0.5131\times 10^{(-19-(-34))}](https://tex.z-dn.net/?f=%5Cimplies%20f%3D0.5131%5Ctimes%2010%5E%7B%28-19-%28-34%29%29%7D)
![\implies f=0.5131 \times 10^{15}](https://tex.z-dn.net/?f=%5Cimplies%20f%3D0.5131%20%5Ctimes%2010%5E%7B15%7D)
![\implies f=5.131 \times 10^{14}](https://tex.z-dn.net/?f=%5Cimplies%20f%3D5.131%20%5Ctimes%2010%5E%7B14%7D)
7<em>m</em> + 10<em>c</em> (is less than or equal to) 100.
<em>m</em> stands for months and <em>c</em> stands for CDs.
I hope this helps! :)
Answer:
Warm front and Cold Front I believe.
Step-by-step explanation: