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PolarNik [594]
3 years ago
11

Poder Inc. is considering a project that has the following cash flow data. What is the project's payback?Year 0 1 2 3Cash flows

−$750 $300 $325 $350a. 1.91 yearsb. 2.12 yearsc. 2.36 yearsd. 2.59 yearse. 2.85 years
Business
1 answer:
boyakko [2]3 years ago
3 0

Answer:

c. 2.36 years

Explanation:

In the payback, we analyze in how many years the invested amount is recovered. The computation is shown below:

In year 0 = $750

In year 1 = $300

In year 2 = $325

In year 3 = $350

If we sum the first 2 year cash inflows than it would be $625

Now we deduct the $625 from the $750 , so the amount would be $125 as if we added the fourth year cash inflow so the total amount exceed to the initial investment. So, we deduct it

And, the next year cash inflow is $350

So, the payback period equal to

= 2 years + ($125 ÷ $350)

= 2.36 years

In 2.36 yeas, the invested amount is recovered.

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The financial statement effects of the budgeting process are summarized on the cash budget and the capital expenditures budget.
denis23 [38]

Answer:

true

Explanation:

8 0
3 years ago
In A Knight's Tale, three friends are deciding what to do with 15 silver coins they won in a jousting tournament. They can spend
kondaur [170]

Answers:

Correct answer:

1. Investment

2. Trade-off of present for future benefit

Incorrect answers:

1. The only possible decision

2. The consumption of consumer goods.

3 0
3 years ago
Slim made a single deposit of $5,000 in an account that pays 7.2% in 2015. What equal-sized annual withdrawals can Slim make fro
evablogger [386]

Answer:

annual withdrawals is  $1,393.87

Explanation:

given data

Amount Deposited = $5,000

Annual Interest Rate = 7.2%

First withdrawal =  2020

last withdrawal = 2025

solution

we consider equal sized annual withdrawals = x

so we can say that Amount Deposited amount will be as

$5,000 = \frac{x}{(1+0.72)^5} + \frac{x}{(1+0.72)^6} + \frac{x}{(1+0.72)^7} + \frac{x}{(1+0.72)^8} + \frac{x}{(1+0.72)^9} + \frac{x}{(1+0.72)^{10}}       ..........1

we take common here \frac{x}{(1+0.72)^{4}}

so

$5,000 = \frac{x}{(1+0.72)^{4}} \times ( \frac{1}{(1+0.72)^1} + \frac{1}{(1+0.72)^2} + \frac{1}{(1+0.72)^3} + \frac{1}{(1+0.72)^4} + \frac{1}{(1+0.72)^5} + \frac{1}{(1+0.72)^{6}} )      

solve it we get

x = $1,393.87  

so that annual withdrawals is  $1,393.87

7 0
2 years ago
On October 1, 2009, the Nintendo Wii's Japanese price dropped from ¥25,000 to ¥20,000. In the three months after the price drop,
kykrilka [37]

Answer:

B) 0.7; inelastic

Explanation:

The computation of the absolute value of the price elasticity of demand is shown below:

Elasticity is

= [(Sales - prior sales) ÷ ( Sales + prior sales) ÷ 2] ÷ [(price - dropped price) ÷ (price - dropped price) ÷ 2

= [(1,040,000 - 890,000) ÷ (1,040,000 + 890,000) ÷ 2] ÷ [(25,000 - 20,000) ÷ (25,000 + 20,000) ÷ 2]

= (150,000 ÷ 965,000) ÷ (5,000 ÷ 22,500)

= 0.15 ÷ 0.22

= 0.7

It is less than one so the demand is inelastic

4 0
3 years ago
Georgina consumes only grapefruits and pineapples. Her utility function is U (x comma y )equals x to the power of 0.8 end expone
vlabodo [156]

Answer:

21

Explanation:

Given that:

The utility function U(x, y) = x^{0.8} y^{0.2}

The budget line income is:

105=4x +3y

The equation MRTS is:

\dfrac{MU_x}{MU_y } =\dfrac{ Px}{Py}

where;

MU_x(x,y) = 0.8 \times x^{0.8-1}\times y^{0.2} \\ \\ \implies 0.8 \times x^{-0.2}\times y^{0.2}

MU_y(x,y) = 0.2 \times x^{0.8}\times y^{0.2-1} \\ \\ \implies 0.8 \times x^{0.8}\times y^{-0.8}

and:

P_y= 3

P_x = 4

∴

Using the equation MRTS:

\dfrac{MU_x}{MU_y } =\dfrac{ Px}{Py}

\dfrac{ 0.8 \times x^{-0.2}\times y^{0.2} }{0.8 \times x^{0.8}\times y^{-0.8}} = \dfrac{4}{3}

\dfrac{4y }{x} = \dfrac{4}{3}

4x = 12y

x = 12y/4

x = 3y

Replacing the value of x into the budget line income, we have:

105 = 4x + 3y

105 = 4(3y) + 3y

105 = 12y + 3y

105 = 15y

y = 105/15

y = 7

Then, from x = 3y

x = 3(7)

x = 21

Thus, she will consume 21 gapefruits

5 0
2 years ago
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