a case of plastic spoons has 8.400 spoons. there are 8 boxes of spoons in the case. how many spoons are in each box

Kelko will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $57 and cost an add

Delicious77 [7]

Questions (contd)

(a) For what amount of driving do the two plans cost the same?

(b) What is the cost when the two plans cost the same?

Answer:

(a) 100 miles

(b) $65

Step-by-step explanation:

Given

Plan 1:

$Initial\ Fee = \$57$

$Additional = \$0.08$ per mile

Plan 2:

$Initial\ Fee = \$50$

$Additional = \$0.10$ per mile

Solving (a): Number of miles when both plans are equal

Represent the distance with x and the cost with y

So:

Plan 1:

$y = 57 + 0.08 * x$

Plan 2:

$y = 50 + 0.10 * x$

To solve (a), we equate both plans together; i.e.

$y = y$

$57 + 0.08x = 50 + 0.10x$

Collect Like Terms

$0.08x - 0.10x= 50 - 57$

$-0.02x= -2$

Solve for x

$x = -2/-0.02$

$x = 100$

Hence, 100 mile would cost both plans the same

Solving (b): Cost when both plans are the same:

In this case, we simply substitute 100 for x in any of the y equation.

$y = 57 + 0.08 * x$

$y = 57 + 0.08 * 100$

$y = 57 + 8$

$y = 65$

<em>Hence, the amount is $65</em>

7 0

3 years ago

Bonjour je ne comprend pas cette exercice; si quelqu'un peut m'aider je suis preneuse.

gayaneshka [121]

Answer:

0,24 m

Step-by-step explanation:

La table est un rectanble donc l'angle en haut à droite est de 90°.

Tu connais donc un angle et le côté opposé à l'angle et tu cherche le côté adjacent.

On sait que tan(â) = $\frac{Cote oppose}{Cote adjacent}$ donc :

tan(40)= $\frac{1,27}{x}$

$\frac{1,27}{tan(40)} = x$

donc x ≈ 1,51 m

Le trou du mileu est à $\frac{2,54}{2}$ soit 1,27m du bord.

Donc elle doit taper à 1,51 - 1,27 = 0,24m du trou du milieu.

j'espère avoir été clair.

<h2 />

8 0

2 years ago

What is the minimum number of degrees that an equilateral triangle can be rotated before it carries onto itself?

mash [69]

Since the triangle has equal sides it will carry onto it self at 120, since it can rotate 360 grades only and it has 3 sides so it will rotate in one third of 360 so 120

i hope i helped you

7 0

3 years ago

Read 2 more answers

Write the slope intercept form of the equation of the line through the given point

ozzi

Answer:

y = $-\frac{3}{4}$ x

Step-by-step explanation:

slope-intercept form: y = mx + b

Given: slope(m) = $-\frac{3}{4}$ , point (4, -3)

We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:

-3 = $-\frac{3}{4}$ (4) + b

Solve for b:

-3 = $-\frac{3}{4}$ (4) + b

-3 = -3 + b

0 = b

The value of b is zero. We can now write the equation:

y = $-\frac{3}{4}$ x + 0

y = $-\frac{3}{4}$ x

The equation written in slope-intercept form is: y = $-\frac{3}{4}$ x

8 0

3 years ago

Concerns about the climate change and CO2 reduction have initiated the commercial production of blends of biodiesel (e.g. from r

natta225 [31]

Answer:

a) 99% of the sample means will fall between 0.933 and 0.941.

b) By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .