Answer:

Step-by-step explanation:
Let
.
and

The graph of the two equations are shown in the attachment.
The points where the two graphs intersected are: 
The x-coordinates of the intersection points are the solutions to
.
Therefore the solutions are: 
Answer:
74.31353
=74 m
Step-by-step explanation:
given that three locations are marked next to a river. Points B and C are on the same side of the river, and point A is on the other side of the river. To find the distance AB across a river, a distance BC of 241 meters is laid off on one side of the river. It is found that the angle at point B is 108.6° and the angle at point C is 14.9°.
we have information about triangle ABC as side BC =241, Angle B = 108.6 and angle C = 14.9 degrees.
Hence this is an obtuse scalene triangle.
Angle ∠A = 56.5° (III angle)
Using sine formula we get

So distance AB is 74 metres.
Answer:
28 pounds
Step-by-step explanation:
We have a total of 5 boxes, now we know that each box weighs 9 pounds, therefore:
Total weight = 5 * 9 = 45 pounds
Which means there are 45 pounds in total.
We are told that the limit is exceeded by 17 pounds. To find the limit weight, it is necessary to subtract the total weight and the excess:
45-17 = 28 pounds
Therefore, the maximum weight allowed per shipment is 28 pounds.
Answer:
5^1 in expended from is 5
hope it helps.
The height of the triangle is 48/b or 48 over b. That's all I can tell you with the information given.