The answer I believe is 1/t(x^2-3)
I cant type the crippled check mark symbol
Answer:
y = ± sqrt(x+7)
Step-by-step explanation:
y = x^2 -7 solve for 'x' .... add 7 to both sides
y+7 = x^2 sqrt both sides
+- sqrt(y+7) = x switch 'x' and 'y'
y = +- sqrt(x+7)
Answer:
20 units
Step-by-step explanation:
The polygon has 4 vertices as indicated by the 4 coordinate points given.
(3, 1) and (8, 1) is a horizontal side of length 8 - 3 = 5
Similarly
(3, 6) and (8, 6) is the opposite horizontal side of length 8 - 3 = 5
Points (3, 1) and (3, 6) is a vertical side of length 6 - 1 = 5
(8, 1) and (8, 6) is the opposite side of length 6 - 1 = 5
The polygon is therefore a square of side 5 units.
Perimeter = 4 × 5 = 20 units
how many 3 element subsets of {1, 2, 3, 4, 5, 6, 7, 8, ,9, 10, 11} are there for which the sum of the elements in the subset is
AURORKA [14]
Answer:
There are 155 ways in which these elements casn occur.
Step-by-step explanation:
We want 3 element subsets whose sum are multiples of 3
1+2+3= 6
1+2+6= 9
1+2+9= 12
1+9+11=21
1+3+5=9
1+4+8=12
1+5+6=12
1+6+8=15
1+7+10=18
1+8+9=18
1+9+11=21
2+3+7=12
2+4+6=12
2+4+9=15
2+5+11=18
2+6+7=15
2+7+9=18
2+8+5=15
2+8+11=21
2+9+10=21
3+6+9= 18
3+9+11=21
3+10+11=24
6+9+10=27
6+8+11=27
6+7+11=24
7+8+9= 24
8+9+10=27
7+9+11=27 .........
We have 11 elements
We need a combination of 3
The combinations can be in the form
even+ even+ odd
odd+odd+odd
even + odd+odd
So there are 3 ways in which these elements can occur
Total number of combinations with 3 elements =11C3= 165
There are 6 odd numbers and 5 even numbers.
Number of subsets with 3 odd numbers = 6C3= 20
Number of two even numbers and 1 odd number = 5C2*6C1=10*6= 60
Number of 2 odd and 1 even number = 6C2* 5C1= 5*15= 75
So 20+60+75=155
There are 155 ways in which this combination can occur
Answer:
The Exterior Angle Theorem states that the measure of the exterior angle of a triangle is
equal to the sum of the measures of the two remote interior angles of the triangle. Angle
PMU is an exterior angle to nPBM and its corresponding remote interior angles are /PBM
and /BPM. So, I can calculate the sum of those two angle measures to find the measure
of /PMU
Step-by-step explanation:
