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Elanso [62]
3 years ago
11

(2,8),(7,8) slope of the line​

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

The slope of line is 0 given points (2,8)(7,8)

Step-by-step explanation:

We need to find slope of line given points (2,8),(7,8)

The formula used to find slope of line is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given:

x_1=2, y_1=8, x_2=7 \ and \ y_2=8

Finding slope using formula:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{8-8}{7-2}\\Slope=\frac{0}{5}\\Slope=0

So, the slope of line is 0

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Let f be defined by the function f(x) = 1/(x^2+9)
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(a)

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\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

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\displaystyle\sum_{n=3}^\infty\frac1{n^2}

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\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

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