Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Answer:
public class Main
{
public static void main(String[] args) {
char greekLetter = '^';
System.out.println(greekLetter);
}
}
Explanation:
Create a char variable called greekLetter and set it to the ^
Print the greekLetter to the screen
<span>The main trade-off that all investors must consider is Risk vs Return
In the end, all the techniques that implemented in investing process is aimed for nothing other than profit.
Current market trend dictates that potential return tend to be higher the riskier the investment is and vice versa.
</span>
Sorry the website wasn’t working for me
Answer:
Have a great day, Here is the answer to your question:
It will take around 18 seconds
Explanation:
So in principle 1GB of data to be uploaded running at peak speed is suggested to take around 18 seconds but in fact, DCD test results show USB 2.0 takes 3 minutes 18 seconds to complete a 1GB switch. Whereas USB 3.0 can accommodate up to 5gbps of data transferred-more than 10 times faster than its predecessor.
