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4 years ago

Please help & explain! 45 points :)

Mathematics

1 answer:

jek_recluse [69]4 years ago

4 0

Hello there,

the answer you are looking for will be
a) it has reflectional symmetry with 16 lines of symmetry

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17% of 51 is what number I WILL GIVE BRAINLIEST

kramer

Answer:

8.67

Step-by-step explanation:

(using proportion method)

51 * 17 = 867

100 * x = 100x

867 / 100x = 8.67

7 0

3 years ago

PLZ HELP WILL MARK BRAINLEST +10 POINTS

mixas84 [53]

Answer:

It's C

The X and Y coordinates are both negative

Step-by-step explanation:

Quadrant 1- negative and positive

Quadrant 2- positive and positive

Quadrant 3- negative and negative

Quadrant 4-positive and negative

7 0

3 years ago

135 + 230+100+100+1000

PIT_PIT [208]

Answer:

its 1565!

Step-by-step explanation:

8 0

3 years ago

Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky

cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable X is defined as the number of stars in a given volume of space.

$X\sim \text{Poisson}\ (\lambda=1)$

The probability mass function of X is:

$p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}$

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

$P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184$

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

$P(X\geq 3)=1-P(X$

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in t cubic light years there will be, [t × (1/16)] stars.

7 0

3 years ago

Find the slope of a line that passes through (3, 4) and (-2, 4).

kupik [55]

The slope of the line passing through the points $(x_1,y_1)$ and $(x_2,y_2)$ is

$\dfrac{y_2-y_1}{x_2-x_1}.$

For the points (3, 4) and (-2, 4) the slope of the line is

$\dfrac{4-4}{-2-3}=\dfrac{0}{-5}=0.$

Answer: correct choice is B

4 0

4 years ago

Read 2 more answers