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3 years ago

Evaluate : 5 - 3 x when x = - 7 Substitute - 7 for x.

Mathematics

2 answers:

viva [34]3 years ago

5 0

Answer:

The answer is 26 Hope this helps!

monitta3 years ago

4 0

Answer:

26 because if x= -7 then -3 X - 7 = +21

+21 +5 = 26

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5c+ 3 < 28 or -4c-2< 14 for c.

sweet-ann [11.9K]

Answer:

c<5, and c>-4.

Steps used for answers:

5c+3<28 =

1. Subtract 3 from both sides.

5c<28-3

2. Simplify 28-3 to 25.

5c<25

3. Divide both sides by 5.

c<25/5

4. Simplify 25/5 to 5.

c<5

-----------------------

-4c-2<14 =

1. Add 2 to both sides.

-4c<14+2

2. Simplify 14+2 to 16.

-4c<16

3. Divide both sides by -4.

c>-16/4

4. Simplify 16/4 to 4.

c>−4

Done by NeighborhoodDealer

3 0

2 years ago

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Write a function rule for the statements

WINSTONCH [101]

Step-by-step explanation:

x. | y

1 | -4

2 | 0

3 | 4

Is this correct?

3 0

2 years ago

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If x=5^a, find the value of 5x. How?

Yakvenalex [24]

Answer:

$5x = 5^{(a+1)}$

Step-by-step explanation:

Here is a problem with the concept of properties of the exponent.

We are given $x = 5^{a}$ and we have to find the value of 5x.

Now, $5x = 5 \times 5^{a}$ {Since we are given that $x = 5^{a}$ }

⇒ $5x = 5^{1} \times 5^{a}$ {Since we can write $x = x^{1}$ }

⇒ $5x = 5^{(a+1)}$ {Since we know the formula of exponent as $x^{m} \times x^{n} = x^{(m + n)}$ }

(Answer)

7 0

3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

3 years ago

Plz help me I need to finish this today!!!!!

Alexxandr [17]

Answer:

B) Elizabeth is wrong.

Step-by-step explanation:

She multiplied. 2 and 3 when she was supposed to divide 36 by 2 instead. when coming across multiplication and division do whichever is first from going left to right

4 0

3 years ago

Read 2 more answers