Let's call a child's ticket  and an adult's ticket
 and an adult's ticket  . From this, we can say:
. From this, we can say:
 ,
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
 .
.
Given these values, we can say:
 ,
,
since each adult ticket  costs 17,000 and each child's ticket
 costs 17,000 and each child's ticket  costs 12,750, and these costs sum to 1,653,250.
 costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:


Let's solve:


- Find  on its own, which will allow us to substitute it into the first equation on its own, which will allow us to substitute it into the first equation

- Substitute in  for for 

- Apply the Distributive Property


- Subtract 1972000 from both sides of the equation and multiply both sides by -1

We have now found that 75 child's tickets were sold. Thus,
 ,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
 
        
             
        
        
        
Answer:
- Yes, diagonals bisect each other
Step-by-step explanation:
<em>See attached</em>
Plot the points on the coordinate plane
Visually, it is seen that the diagonals bisect each other.
We can prove this by calculating midpoints of AC and BD
<u>Midpoint of AC has coordinates of:</u>
- x = (1 - 1)/2 = 0
- y = (4 - 4)/2 = 0
<u>Midpoint of BD has coordinates of:</u>
- x = (4 - 4)/2 = 0
- y = (-1 + 1)/2 = 0
As per calculations the origin is the bisector of the diagonals.
 
        
             
        
        
        
Answer:
a) 0.50575, 
b) 0.042
Step-by-step explanation:
Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.
If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).
And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:
a) All three times the person bought good goods.
P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) = 
P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) = 
(0.7)(0.85)(0.85) = 
0.50575       
b) Only the second time that person buys a bad product.
P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) = 
P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) = 
(0.7)(1-0.85)(1-0.6) = 
(0.7)(0.15)(0.4) = 
0.042
 
        
             
        
        
        
The measure of angle 1 would be (3x+2) and the measure of angle 2 would be (5x+10). There is no way to determine the exact degrees of these angles because not enough information is given.
        
             
        
        
        
Answer:
I don't know but maybe 3 in a half