Answer:
It should be A) 54
Step-by-step explanation:
32 + 14 + 8 = 54
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
60 percent of 52 is 31.2, about 30.
Hope this helps, Tiara
Answer:
x = -1, y= -5
Step-by-step explanation:
y=-x-6
y=x-4
Since both equations are equal to y we can set them equal to each other
-x-6 = x-4
Add x to each side
-x-6+x = x-4+x
-6 = 2x-4
Add 4 to each side
-6+4 = 2x-4+4
-2 =2x
Divide by 2
-2/2 = 2x/2
-1 = x
now find y
y = x-4
y = -1-4
y = -5
