Answer:
36years
Step-by-step explanation:
Let charity present age be x
Charity daughter present age be y
Charity husband present age be z
If the sum of their ages ten years to come is 117, then;
10+x+10+y+10+z = 117
30+x+y+z = 117
x+y+z = 87 ... 1
If charity is four times as old as her daughter, then;
x = 4y
y = x/4 ... 2
If she is also six years younger than her husband, then;
x = z- 6
z = x+6 .. 3
Substitute 2 and 3 into 1;
x + x/4 + (x+6) = 87
Multiply through by 4
4x + x + 4(x+6) = 4(87)
5x+4x+24 = 348
9x = 348 - 24
9x = 324
x = 324/9
x = 36
hence Charity is 36years old today
Answer:
true
Step-by-step explanation:
|x-6| < 1 + 10 (move 10 to the right side)
|x-6| < 11
1)x-6 < 11 (here x >= 6)
2)-x+6 < 11 (here x < 6)
1)x<17
2)x>-5
so we get -5 < x < 17
the answer: (-5; 17)
Answer:
0.25
Step-by-step explanation:
hope that helps!!!!!!!!!!!!!!!!!!!! :)
