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s344n2d4d5 [400]
4 years ago
7

Help help help help

Mathematics
1 answer:
OlgaM077 [116]4 years ago
5 0

Answer:

11

Step-by-step explanation:

4^3/2 - 7 × 3

64/2 - 21

32 - 21 = 11

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Area of a trapezoid please help
Lena [83]

Answer:

A= 30

Step-by-step explanation:

A= a+b over 2

h= 5+15 over 2 times that by 3 to get 30

5 0
3 years ago
Need help due in 10!
lakkis [162]

Answer:

1. (28-2)x

2.(12+6)x

3.(15+1)x

Step-by-step explanation:

8 0
3 years ago
Where can u place these at tell me
Alex777 [14]
The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2

Hope this helps :)
5 0
4 years ago
A florist can make a grand arrangement in 18 minutes or a simple arrangement in 10 minutes. The florist makes at least twice as
Colt1911 [192]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of simple arrangements and y be the number of grand arrangements.

1. The florist makes at least twice as many of the simple arrangements as the grand arrangements, so

x\ge 2y

2. A florist can make a grand arrangement in 18 minutes =\dfrac{3}{10} hour, then he can make y arrangements in \dfrac{3}{10}y hours.

A florist can make  a simple arrangement in 10 minutes =\dfrac{1}{6} hour, so he can make x arrangements in \dfrac{1}{6}x hours.

The florist can work only 40 hours per week, then

\dfrac{3}{10}y+\dfrac{1}{6}x\le 40

3. The profit on the simple arrangement is $10, then the profit on x simple arrangements is $10x.

The profit on the grand arrangement is $25, then the profit on y grand arrangements is $25y.

Total profit: $(10x+25y)

Plot first two inequalities and find the point where the profit is maximum. This point is point of intersection of lines x=2y and \dfrac{3}{10}y+\dfrac{1}{6}x=40

But this point has not integer coordinates. The nearest point with two integer coordinates is (126,63), then the maximum profit is

\$(10\cdot 126+25\cdot 63)=\$2,835

8 0
3 years ago
find the length of the hypotenuse of a right triangle with legs measuring 6 cm and 9 cm. round your answer to the nearest tenth
Xelga [282]
I would say all you have to do is add those sides up then minus it with the total you’re trying to find
7 0
3 years ago
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