paul paid $2.80 each,wholesale for 200 novelty memory sticks.he marked up the price 90%. find the selling price.

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

5 0

2.8*1.9= 2.8 + 2.8*.90= 5.32

Inessa [10]3 years ago

4 0

He bought 200 of them
200*2.80=$560
marked up 90%
90% of 560=0.9*560=504
560+504=1064
he sold all 200 for a total of 1064, or an average price of $5.32 each

You might be interested in

I need help!!!!!!!!!!!!!!

Sloan [31]

With what? There is no question

3 0

3 years ago

NNNNNNNNEED HELP!!!!!

Neko [114]

Answer: First box=3, second box=4, third box=0, last box=2

Step-by-step explanation: Do the math for the boxes.

5 0

3 years ago

The tallest escalator on the London Underground system is at Angel Station. It rises to a height of 90 feet over a horizontal di

Amanda [17]

0.222 is your answer

5 0

4 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$