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3 years ago

There are 32 students in a class. Nine of those students are women. What percent are men?

Mathematics

1 answer:

QveST [7]3 years ago

5 0

Answer:

72%

Step-by-step explanation:

you can divide part of a whole by the whole to get a decimal

this decimal is the percentage when you move the decimal 2 places to the right

32 - 9 = 23 men

23/32 = .72 (rounded)

.72 = 72%

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Is the relation { (5, 2), (-1, 6), (8, -2), (5, 3)} a function? why or why not? list the domain and range

Tasya [4]

Answer:

it is not a function because the input 5 (x) has more than one output (y)

domain (5,-1,8)

range (2,6,-2,3)

Step-by-step explanation:

5 0

2 years ago

How do you find the range in a set of numbers?

Angelina_Jolie [31]

Answer:

first order the data from least to greatest. Then subtract the smallest value from the largest value in the set

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

If Angie’s gross pay for 21.5 hours was $282.08, what was her pay per hour?

xxMikexx [17]

Answer:

$13.12 per hour

Step-by-step explanation:

Take the total pay and divide by the number of hours

$282.08/21.5 hours

$13.12 per hour

8 0

2 years ago

Read 2 more answers

The reacttimes data set has 50 observations of human reaction times to a physical stimulus. The reaction times are named times a

scoundrel [369]

Solution: The formula for mean is:

$Mean=\frac{\sum x}{n}$

Where:

$\sum x$ is the sum of given observations

$n$ is the number of observations

$\sum x=87.12$

$n=50$

$\therefore Mean =\frac{87.12}{50}= 1.74$ rounded to two decimal places

To find the median, we need to first arrange the data in ascending order but we are already given the data in ascending order.

Therefore, the median is:

$Median=\left(\frac{n+1}{2} \right)^{th} item$

$=\left(\frac{51}{2} \right)^{th} item$

$=25.5^{th} item$

$=1.52+0.5(1.54-1.52)$

$=1.52+0.01$

$=1.53$

Therefore, the median = 1.53

4 0

2 years ago

Solve for x: 2(x+2)-4x+8

ddd [48]

ANSWER:
2(-x+6)
If you want it simplified the answer is 2x+12
Hopefully I helped

3 0

2 years ago