$\displaystyle\dfrac{1}{\sec x(1-\sin x)}=\dfrac{\cos x}{1-\sin x}\\\\\\\int \dfrac{dx}{\sec x(1-\sin x)}=\int\dfrac{\cos x\, dx}{1-\sin x}\\\\\\u=1-\sin x\\du=-\cos x\, dx\\\\\int \dfrac{\cos x\, dx}{1-\sin x}=\int \dfrac{-du }{u}=-\int \dfrac{du}{u}=-\ln |u|+C=-\ln|1-\sin x|+C$

4 0

2 years ago

Can you figure out the answer please

miss Akunina [59]

Answer:

h = — 10.071

Step-by-step explanation:

Look at the picture for my work.

7 0

3 years ago

On a quiz, tina scored 4 points more than julia and earned 2 points in extra credic. Enter an expression that represent tina's s

andre [41]

Julia’s score is y and Tina’s score is y + 6.

Step-by-step explanation:

Let us take Julia’s score be y.

First Tina scored 4 points more than Julia, so the expression is y + 4.

Then, Tina earned 2 points as extra credic, now the expression becomes

(y + 4) + 2 = y + 6.

Hence Julia’s score is y and Tina’s score is y + 6.

7 0

3 years ago

Order pairs of x-5y=-1

Alisiya [41]

Answer: (0,1)

Step-by-step explanation:

x-5y=-1

+5y

x= -1+5y

x+1= 5y

Y intercept would be 1

8 0

3 years ago