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3 years ago

14

Which type of annuity typically utilizes mutual funds

1 answer:

Vlada [557]3 years ago

4 0

Answer:
variable annuity typically provides mutual funds

Explanation:
1- Annuity is commonly used financial product among the retirees to get regular income.
2- Annuity usually pays a fixed amount each month
3- variable annuity is different because the amount of funds paid each month varies depending on how the investment performs each month.

Hope this helps :)

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Find the value of P when P = 2Q + 4R when Q = -4 and R = 5

Alenkinab [10]

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4 years ago

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Snezhnost [94]

Answer:

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3 years ago

Please help 1-5 and please show how you got the answers

nirvana33 [79]

Answer:

Step-by-step explanation:

1) 2x + y = 3 -(1)

-3x + 2y = -8 -(2)

(1) x 2 => 4x + 2y = 6 -(3)

(3) - (2)

=> 4x + 2y + 3x - 2y = 6 + 8

=> 7x = 14

=> x = 2

=> 2(2) + y = 3

=> y = 3 - 4 = -1

2) 6x + 7y = -9 -(1)

-4x - 5y = 5 -(2)

(1) x 4 => 24x + 28y = -36 -(3)

(2) x 6 => -24x - 30y = 30 -(4)

(3) + (4)

=> 24x + 28y - 24x - 30y = -36 + 30

=> -2y = -6

=> y = 3

=> 6x + 7(3) = -9

=> 6x = -30

=> x = -5

3) -x - 7y = 9 -(1)

-x + 9y = -23 -(2)

(1) - (2)

=> -x - 7y + x - 9y = 9 + 23

=> -16y = 32

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=> x = 23

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(1) + (2)

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=> x - 5(-1) = 1

=> x = -5

5) -2x + y = 10 -(1)

4x + y = -14 -(2)

(1) - (2)

=> -6x = 24

=> x = -4

=> 4(-4) + y = -14

=> y = -14 + 16 = 2

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2 years ago

Hi. I need help with these questions (see image)<br>Please show workings.<br>

pantera1 [17]

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

$\frac{dy}{dx}$ = f'(g(x)) × g'(x) ← chain rule

and the standard derivatives

$\frac{d}{dx}$ ( $log_{a}$ x ) = $\frac{1}{xlna}$ , $\frac{d}{dx}$ (lnx) = $\frac{1}{x}$

(a)

Given

y = $log_{a}$ $\sqrt{(1+x)}$

$\frac{dy}{dx}$ = $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{d}{dx}$ ( $(1+x)^{\frac{1}{2} }$

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2}$ $(1+x)^{-\frac{1}{2} }$ × $\frac{d}{dx}$ (1 + x)

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2\sqrt{(1+x)} }$ × 1

= $\frac{1}{2lna(1+x)}$

= $\frac{1}{(1+x)lna^2}$

(b)

Given

y = ln sinx

$\frac{dy}{dx}$ = $\frac{1}{sinx}$ × $\frac{d}{dx}$ (sinx)

= $\frac{1}{sinx}$ × cosx

= $\frac{cosx}{sinx}$

= cotx

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Answer:

in the attachement below

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3 years ago

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