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yulyashka [42]
3 years ago
15

What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?

Mathematics
1 answer:
blagie [28]3 years ago
3 0
Your answer would be c)

Point slope form formula is y-y1=m(x-x1), where m is slope and x1 and y1 are coordinates to a point on your graph.

To find your slope, you will need to use the formula y2-y1/x2-x1, also known as change in y over change in x or rise over run. So then you would have [3-(-5)]/[2-(-2)], which gives you slope (m) =2.

Then you can rule out letters A and D because the slope in those answers is incorrect (-2).

Next, you take your coordinate points (x,y) (2,3) and substitute them in your equation.

So, you have y-3=2(x-2)

*notice that the difference between b and c is that the x and y values on the coordinate points are in the wrong places. You need to have y-(your y coordinate) and then x-(your x coordinate) in your point slope equation.

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A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea
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Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that n = 11

Each question has five choices.

This means that p = \frac{1}{5} = 0.2

(a) Find P (6)

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859

P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362

P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953

P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389

Then

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611

P(More than 3) = 0.1611

8 0
4 years ago
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