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2 years ago

What number makes 3 and 71 divisible by 9?

1 answer:

4 0

3 only
7 only 
1 only 
1, 4, and 7 
do you mean which digit is added to 371 so that it is divisible by 3 
test for 3, sum of digits divisible by 3 
3 + 7 + 1 = 11 
if you add 3, 11 + 3 = 14 not divisible by 3 
if you add 7, 11+ 7 = 18 divisible by 3 
if you add 1, 11+ 1 = 12 divisible by 3 
if you add 1, 4, 7 divisible by 3

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solong [7]

Answer:

4 √6

Step-by-step explanation:

We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:

m²+z² = (8+4)² = 12²

4²+n²=z²

8²+n²=m²

We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.

4²+n²=z²

subtract 4²=16 from both sides

z²-16 = n²

plug that into the third equation

64 + z² - 16 = m²

48 + z² = m²

subtract 48 from both sides to solve for z²

z² = m² - 48

plug that into the first equation

m² + m² - 48 = 144

2m² - 48 = 144

add 48 to both sides to isolate the m² and its coefficient

192 = 2m²

divide both sides by 2 to isolate the m²

96 = m²

square root both sides to solve for m

√96 = m

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1 year ago

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3 years ago

Can you please help me find the area? Thank you. :)))

Phoenix [80]

The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

$A=w\cdot l$

For our rectangle w=12 in and l=20 in, the area is:

$\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}$

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

$\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}$

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

$A=\frac{b\cdot h}{2}$

For our triangle, the base is b=4in and the height is h=6in, then the area is:

$\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}$

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

$\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}$

The area of the figure is 228in²

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1 year ago