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svp [43]
2 years ago
5

4a 5(a-3)=2 3a what is the answer

Mathematics
2 answers:
Vitek1552 [10]2 years ago
7 0
4a + 5(a - 3) = 2 + 3a

4a + 5*a - 5*3 = 2 + 3a

4a + 5a - 15 = 2 + 3a

9a - 15 = 2 + 3a

9a - 3a = 2 + 15

6a = 17            

Divide both sides by 6

6a/6 = 17/6

a = 17/6

Hope this helps.
alexdok [17]2 years ago
4 0
4a + 5a - 15 = 2 + 3a
6a = 17
a = 17/6
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Answer:

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Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = \left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]

B= \left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * \left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]  + 1 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-1) \left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]

AB Column 2 = (-1)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + 2\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-2)\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}4\\3\\0\end{array}\right]

AB Column 3 = (0)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + (1)\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + 4\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}6\\5\\-4\end{array}\right]

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

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