Answer:
468 ways
Step-by-step explanation:
Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts
To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.
Solution:
A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.
Number of appetizers = 5
Number of main courses = 4
Number of desserts = 8
Number of ways of choosing k terms from n terms = 
Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = 
So, this can be done in 468 ways.
Answer:
2.45, -2.45
Step-by-step explanation:
Since the equation has only one term in the unknown "x", we can solve for it isolating "x" on one side of the equal sign:
Which we can round to: x = - 2.45 and x = 2.45
There's 6.Because there's 2 per mile. So 3x2 =6
Answer:
Add 3 over each interval
Step-by-step explanation:
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
