I need help plz, i will give brainliest for the correct answer
1 answer:
Answer:
- f'(1) exists: f'(1) = -2
- f'(0) DNE
Step-by-step explanation:
<h3>a)</h3>The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...
f'(x) = -2x . . . . . for x > 0
Then at x = 1, the derivative is ...
f'(1) = -2(1)
f'(1) = -2
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<h3>b)</h3>The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.
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Answer:
Step-by-step explanation:
Q1. The limit from the right is -4. (The limit from the left, and the value of f(3) are different, but that doesn't matter for the question asked. Taken together, they mean that the limit as x approaches 3 does not exist. But that is not the question asked.)
Q2. f(x) = 4/x.
f'(x) = -4/x^2, so f'(2) = -4/2^2 = -1.
Q3. Since the denominator is zero at x=7, the only answer choice that makes any sense is the first one:
-∞; x = 7
It also happens to be the right one.
