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FromTheMoon [43]
2 years ago
11

I need help plz, i will give brainliest for the correct answer

Mathematics
1 answer:
DanielleElmas [232]2 years ago
6 0

Answer:

  • f'(1) exists: f'(1) = -2
  • f'(0) DNE

Step-by-step explanation:

<h3>a)</h3>

The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...

  f'(x) = -2x . . . . . for x > 0

Then at x = 1, the derivative is ...

  f'(1) = -2(1)

  f'(1) = -2

__

<h3>b)</h3>

The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.

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Pani-rosa [81]

Answer:

Inequality:

120 + 0.05x ≥ 200

Solution:

x ≥ $1,600

Her total weekly sales must be equal to or greater than $1,600

Step-by-step explanation:

Let x represent the weekly sales she must make to reach her goal.

Given;

Pay rate = $8

Weekly total work hours = 15 hours

Commission on sales = 5% = 0.05

Total weekly earnings is;

8×15 + 0.05×x

120 + 0.05x

Minimum Weekly target earnings = $200

So;

120 + 0.05x ≥ 200

Solving the inequality equation;

0.05x ≥ 200 - 120

0.05x ≥ 80

x ≥ 80/0.05

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6 0
3 years ago
Every third visitors to a museum gets a free bumper sticker. Every fifth visitor to that museum gets a free key chain. Which vis
Rashid [163]
The fifteenth customer will be the first because 5x3=15

8 0
3 years ago
Use the table to solve the inequality x−5≥7.
miskamm [114]

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Step-by-step explanation:

6 0
2 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
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The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
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time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
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We solve this system of equations:

10t=15(t-3)
10t=15t-45
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t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
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