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Crank
3 years ago
15

In the diagram below, \overline{XY}

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0

Answer:

\boxed{15}

Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is XY and the segments are VY and WY.

XY = \sqrt{VY \times WY} = \sqrt{ 3 \times 75} = \sqrt{225} = \mathbf{15}\\\text{The measure of XY is $\large \boxed{\mathbf{15}}$}

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The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel:
Stels [109]

Answer:

SAS postulate

Step-by-step explanation:

In the figure attached, quadrilateral ABCD is shown.

The Side Angle Side (SAS) postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

AB is congruent to DC, and DB is the side common to triangles ABD and BCD. The included angle between sides AB and DB is angle ABD which is congruent with angle BDC, the angle included between sides DB and DC.

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3 years ago
The product of two fractions is 14/9.Write all possible answers
S_A_V [24]

Answer:

Step-by-step explanation:

7/3 * 2/3

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8 0
3 years ago
George is 4 times Dorothy's age. If George is 56, how old is Dorothy? Let d = Dorothy's age.
Yuri [45]
4d=56
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3 0
3 years ago
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The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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