Answer:
2:9 4:8
8:3 24:6
9:7 3:2
18:15 6:6
18:12 12:16
10:40 5:9
12:16 6:7
12:36 12:18
45:15 4:5
those in bold are the answer
9514 1404 393
Answer:
obtuse
Step-by-step explanation:
The law of cosines tells you ...
b² = a² +c² -2ac·cos(B)
Substituting for a²+c² using the given equation, we have ...
b² = b²·cos(B)² -2ac·cos(B)
We can subtract b² to get a quadratic in standard form for cos(B).
b²·cos(B)² -2ac·cos(B) -b² = 0
Solving this using the quadratic formula gives ...

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.
1. You have the function 
2. You know that
with
, because the division by zero is not defined. So ,
for
where
is a integer number.
3. Then, to find the domain of the function given in the problem, you must make 
Where
is odd number.
4. Therefore:

5. Finally, the domain is: 
The answer is: 
The product of x and 6: 6(x)
is at least -17: ≥ 17
6x ≥ 17 is your answer
hope this helps
Answer:
<em>The options are not visible enough (See Explanation)</em>
Step-by-step explanation:
Given
x:- 1 || 2 || 3 || 4 || 5
y:- 13 || 22 || 37 || 58 || 85
Required
Determine if the function is quadratic
Calculate the difference between the values of y




<em>The resulting difference are: 9 || 15 || 21 || 27</em>
Next; Calculate the difference between the difference of values of y



<em>The resulting difference are: 6 || 6 || 6</em>
<em>For the function to be quadratic, the above difference must be the same and since they are the same (6), then the function represents a quadratic function.</em>