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kompoz [17]
3 years ago
13

Find the distance between the points X and Y shown in the figure.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

Dude go and sleep, after waking up you will automatically get the answer.

believe me......

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What is the point (-9,-3) after rotating 180 counterclockwise
sleet_krkn [62]

Answer:

(9, 3)

Step-by-step explanation:

When a point is rotated 180 degrees, you take the opposite of the coordinates.

i.e (5, 6) ---> (-5, -6)

4 0
2 years ago
Given right triangle A w/a hypotenuse length of x+4 and a leg of x, and right triangle B, w/ a hypotense length of 3y and a leg
alex41 [277]

Answer:

Value is x=8 and y=4

Step-by-step explanation:

Given : A right triangle 'A'  hypotenuse length of x+4 and a leg of x,

and right triangle 'B' hypotenuse length of 3y and a leg length of y+4

To find : For what values of x and y are the triangles congruent by HL?  

Solution :

Triangle A,

Hypotenuse: x+4

Leg: x

Triangle B,  

Hypotenuse: 3y

Leg: y+4  

Since the triangle A and B are congruent so, the sides of triangles are equal.

x+4=3y    (Hypotenuse are equal)  ..........[1]

and x=y+4   (Legs are equal)   ..........[2]

Solving the equation of system,

Put the value of x from [2] in [1],

x+4=3y

y+4+4=3y

8=2y

y=4

Substitute y in [2],

x=y+4

x=4+4

x=8

Therefore, The value of x=8 and y=4

Verifying for the values of x and y:

Triangle A,

Hypotenuse: x+4=8+4=12

Leg: x=8

Triangle B,  

Hypotenuse: 3y=3(4)=12

Leg: y+4=4+4=8

Both hypotenuses and both legs are equal hence they are congruent.

6 0
3 years ago
Based on a study, a theme park has reported that typical patrons were willing to pay
Damm [24]

Answer:

A and D

Step-by-step explanation:

3 0
3 years ago
What is the value of 1/3x-3/4 when x =1/4
satela [25.4K]

Answer:

The value of 1/3x-3/4 when x=1/4 is 0.08333 repeated.

Step-by-step explanation:

7 0
3 years ago
The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.
ololo11 [35]

Answer: (a)  {a, ar, ar², ar³, ar⁴, ar⁵...}, (b)  arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.  

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0
3 years ago
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