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1 year ago

Function f is shown below f(-3) f(4) find x when f(x) = 5 find x when f(x)= -3

Mathematics

1 answer:

hjlf1 year ago

4 0

Answer:

See below ~

Step-by-step explanation:

Based on the graph,

f(-3)

f(-3) = 0

2. f(4)

f(4) = -3

3. x when f(x) = 5

f(x) = 5
x = 0

4. x when f(x) = -3

f(x) = -3
x = ±4

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How to solve this one

ivolga24 [154]

The x,y = -6, -5. Hope this helped, and have a great day! :D

6 0

2 years ago

Which of the following is the graph of y=sqr root -x-3

Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

$y=\sqrt{-x-3}$

we know that

The radicand must be greater than or equal to zero

$(-x-3)\geq 0$

solve for x

Adds 3 both sides

$-x\geq 0+3$

$-x\geq 3$

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x\leq -3$

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

3 0

2 years ago

(5) Rhea ran 6 laps on a track. Each lap is 200 yards. Rhea's average speed for

sashaice [31]

Answer:

72 yd / min

Step-by-step explanation:

The first thing is to fully calculate the distance traveled, each lap is 200 yards and how 6 laps would be:

200 * 6 = 1200

Now, let's divide the race into how the statement tells us:

1200 * 2/3 = 800

1200 * 1/3 = 400

That is, in the first 800 yards it goes to 80 yd / min and then in the remaining 400 yards it goes to 60 yd / min, let's calculate the time Rhea lasted:

800/80 = 10 min

400/60 = 6,667 min

Which means that in total it would be:

10 + 6,667 = 16,667

In other words, Rhea took 16,667 minutes to travel 1,200 yards, so the speed would be:

1200 / 16,667 = 72

Therefore the average Rhea speed was 72 yd / min

7 0

2 years ago

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$