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lianna [129]
3 years ago
5

8.235 x 10-4 = ? standard form

Mathematics
2 answers:
nexus9112 [7]3 years ago
7 0

Answer:

I think it is NaN*10^0

Andreyy893 years ago
6 0
0.0008235 I think That’s the answer
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write a real world example that could be solved by using the inequality 4x+8≥32.then solve the inequality
V125BC [204]
Sally had 8 dollars right before she was paid for working 4 hours. Sally has at least 32 dollars now.
how much was she paid per hour?
4x + 8 \geqslant 32
4x \geqslant 24
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6 0
3 years ago
Vroom Vacuums sells the Tornado vacuum cleaner. Each Tornado has a one-year warranty that covers any product defects. When custo
Aleksandr [31]

Answer:

Performance obligation:

Revenue is recognized by a company if the contractual obligations are satisfied by transferring the goods and services to a customer. A performance obligation must be identified and separated.

The purchase of vacuum cleaner contract gives raise to only one implied performance obligation. The warranty given is not a performance obligation but a quality assurance. And the warranty cost does not satisfy the contractual obligation of sale.

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The extended warranty for a period of three years is sold separately. This is a separate performance obligation since the warranty for quality assurance is extended beyond the original period of one year.

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Therefore, there exists only one performance obligation in the contract.

8 0
3 years ago
Kyra solved the following quadratic equation. What was the error, if any, that she made?
podryga [215]
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5 0
3 years ago
A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
How can i do 3×3×11 6 grade
allsm [11]
You can start by doing 3×3 which is 9 than get the 9 and multiply it by 11 which would be 99
5 0
3 years ago
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