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Kobotan [32]
2 years ago
5

Hhshjsjdjsbzbjajsjjdbzbannenxbzbbandbsbnanandnz

Mathematics
2 answers:
Pachacha [2.7K]2 years ago
8 0
Nice keyboard spam and free points
exis [7]2 years ago
4 0

Answer:

rfrjbgithbgihebgherhghtigbihebg

Step-by-step explanation:

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Evaluate 9 C 5.<br><br> 24 <br><br> 3,024<br><br> 45<br><br> 126
Tanzania [10]
A quics way to do this :-

9C5    = 9*8*7*6*5              3 * 7 * 6   =    126
             -------------        =     
              5*4*3*2*1                 
5 0
3 years ago
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in the year 2005 a company made $6.6 million in profit for each consecutive year after that their profit increase by 9% how much
posledela

Answer:

$9.3 million

Step-by-step explanation:

Given that the company profit increases by 9% yearly from 2005.

Using the exponential growth formula;

A = P(1+r)^(t) .....1

Where;

A = final amount/value of profit

P = initial amount/value = $6.6 million

r = growth rate yearly = 9% = 0.09

t = time of growth in years = 2009 - 2005 = 4 years

Substituting the values;

A = 6.6(1+0.09)^(4)

A = 6.6(1.09)^(4)

A = 9.3164386 million

A = $9.3 million

The companies profit in the year 2009 to the nearest 10th of $1 million is $9.3 million

5 0
3 years ago
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