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Marysya12 [62]
3 years ago
9

Find four consecutive numbers whose sum equals 218

Mathematics
1 answer:
Softa [21]3 years ago
4 0

Answer: 53, 54, 55, and 56

Step-by-step explanation: This problem states that the sum of 4 consecutive numbers is 218 and it asks us to find the numbers.

4 consecutive numbers can be represented as followed.

X ⇒ <em>first number</em>

X + 1 ⇒ <em>second number</em>

X + 2 ⇒ <em>third number</em>

X + 3 ⇒ <em>fourth number</em>

Since the sum of our 4 consecutive numbers is 218, we can set up an equation to represent this.

X + X + 1 + X + 2 + X + 3 = 218

On the left side of the equation, we can combine our x's and our numbers.

4x + 6 = 218

      -6     -6   ← <em><u>subtract 6 from both sides of the equation</u></em>

4x = 212

÷4    ÷4   ← <u><em>divide both sides of the equation by 4</em></u>

 <u>X = 53</u>

<u />

X ⇒ <em>first number   = 53</em>

X + 1 ⇒ <em>second number   = 54</em>

X + 2 ⇒ <em>third number   = 55</em>

X + 3 ⇒ <em>fourth number   = 56</em>

<em />

<em>Therefore, our 4 consecutive numbers are </em><em>53</em><em>, </em><em>54</em><em>, </em><em>55</em><em>, and </em><em>56</em><em>.</em>

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