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GenaCL600 [577]
3 years ago
8

John can reach 60 centimeters above the top of his head. If John is 2 meters tall, how high can he reach?

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
He can reach 2 meters and 60 centimeters which can be simplified to 260 centimeters since there are 100 centimeters in 1 meter.
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6) BRAINLIEST AND 15 + POINTS :)
aniked [119]

Answer:

C

Step-by-step explanation:

y》0.5x + 1.8

x = 4, y = 4.5

4.5》0.5(4) + 1.8

4.5》3.8 (true)

7 0
3 years ago
Will mark brainliest and thank you!!!!<br><br> Please help!!!!!
Vaselesa [24]

Answer:

32m^4 + 12m^3 = 4m^3(8m + 3)  ---------->correct

40m^6 - 4 = 4(10m^6 - 1) ---------->correct

Step-by-step explanation:

32m^4 + 12m^3 = 4m^3(8m + 3)  ---------->correct

40m^6 - 4 = 4(10m^6 - 1) ---------->correct

15m^3 - 6m = 3m(5m^2 - 2) , so it's not correct if answer : 3m(5m^2 - 6m)

6m^2 + 18m = 6m(m + 3) , so it's not correct if answer : 6m^2(1 + 3)

6 0
3 years ago
Read 2 more answers
A pet store sells dog food in a 3-pound bag for $12.00 and a 5-pound bag for $14.25. Which bag of dog food is the better buy? Ex
Bess [88]

The 5-pound bag is better value.

The easiest way to compare and find out which is a better buy is to find out how much is being charged for 1-pound of food in each bag.

$12 is divided by 3 beacuse it's a 3-pound bag and we are aiming to find what 1-pound is equal to.

$12 ÷ 3 = $4

So the first bag charges $4 per pound of food.

Then use the same method for the 5-pound bag.

$14.25 ÷ 5 = $2.85

So the second charges $2.85 per pound of food.

So as we can see, the 5-pound bag is clearly better value. For each pound of food you are saving $1.15 in comparison to what you would be spending if you opted for the first bag.

Hope this helps!

5 0
3 years ago
For every 20 litres of petrol a car can run for 75 km.
densk [106]

Answer:

<u>52.3 litres</u>.

Step-by-step explanation:

The car consumption is 75/20 = 3.75 km/litre.

Volume of petrol needed to travel 196 km

= 196 / 3.75 = 52.3 litres.

3 0
4 years ago
Reduce 7y + 2y 2 - 7 by 3 - 4y.
NARA [144]

Answer:

D. 2y^2+11y-10.

Step-by-step explanation:

Given:

We need to reduce 7y+2y^2-7 by 3-4y

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

2y^2+7y-7  ⇒ equation 1

Also Arranging other equation we get;

-4y+3   ⇒ equation 2

Now we will subtract equation 2 from equation 1 we get;

(2y^2+7y-7)-(-4y+3)

Now Applying distributive property for the sign we get;

2y^2+7y-7+4y-3

Now Arranging the like terms we get;

2y2+7y-+4y-7-3\\\\2y^2+11y-10

Hence the reduce form of the given equation is 2y^2+11y-10.

7 0
3 years ago
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