This is a ray (Line that extends only one infinitely while the other way has an eventual and perceivable end) that divides an angle (in this case, the angle of a triangle) into two equal parts.

7 0

3 years ago

How do i find the volume of these similar solids? round to the nearest tenth HELP

FromTheMoon [43]

Answer:

The volume of the larger solid is $592.6\ mm^3$

Step-by-step explanation:

The question is

If these solids are similar, find the volume of the larger solid

step 1

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

$z=\frac{x}{y}$

we have

$x=4\ mm\\y=3\ mm$

substitute

$z=\frac{4}{3}$ ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

$z^3=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=250\ mm^3$

substitute the values

$(\frac{4}{3})^3=\frac{x}{250}$

solve for x

$(\frac{64}{27})=\frac{x}{250}$

$x=250(\frac{64}{27})$

$x=592.6\ mm^3$

4 0

3 years ago

Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

$sin(A)=\frac{BC}{AB}$

substitute the values

$sin(A)=\frac{2\sqrt{42}}{23}$

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

3 years ago

Factor out the greatest common factor 20x^4 + 15x^2 - 10x

aleksandr82 [10.1K]

5x(4x^3 + 3x - 2)

There’s a 5 and a x common.

3 0

3 years ago