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horsena [70]
3 years ago
9

Which parabola will have a minimum value vertex?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0

Answer:

What functions?

Step-by-step explanation:

ivolga24 [154]3 years ago
5 0

Answer:

IV Graph

Step-by-step explanation:

the last graph

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Graph this rational equation. Identify the points of discontinuity, holes, vertical asymptotes, x-intercepts, and horizontal asy
irakobra [83]

Step-by-step explanation:

We have given,

A rational function : f(x) = \frac{x-2}{x-4}

W need to find :

Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.

For no values of x, we get indetermined form (i.e \frac{0}{0}), Hence there is no holes

Vertical Asymptotes:

Plug y=f(x) = ∞ in f(x) to get vertical asymptote   {We can us writing ∞ = \frac{1}{0}}

i.e ∞ = \frac{x-2}{x-4}

or \frac{1}{0}=\frac{x-2}{x-4}

or x-4 =0

or x=4, Hence at x = 4, f(x) has a vertical asymptote

X -intercept :

Plug f(x)=0 , to get x intercept.

i.e 0 = \frac{x-2}{x-4}

or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = \frac{x-2}{x-4} = \frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}

or f(x) = \frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}

or f(x) = 1 = y

hence at y =f(x) = 1, we get horizontal asymptote





4 0
3 years ago
Find a Cartesian equation for the curve and identify it. r=8tanxsecx
ANTONII [103]
R = 8 tan(x) sec(x)

In order to solve this, we are going to use the following:
r = sqrt(x^2 + y^2) //but in this case, we don't need this.
tan(x) = Y / X
X = r cos(x)
Y = r sin(x)

<span>(r cos x)^2 = 8(r sin x)</span>

x^2 = 8y
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3 years ago
Standard deviation of 8, 4, 14, 16, 8
Ivan

Answer:

The answer for standard deviation would be:

4.382

3 0
3 years ago
From the set {30, 42, 84}, use substitution to determine which value of x makes the equation true.
Maru [420]
2,520/x = 60
x = 42, which means your answer is B.

2,520/42 = 60
8 0
2 years ago
F(x) = x + 2x2 - 4x - 3
maks197457 [2]
It is C I believe have a great day
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3 years ago
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