F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
z = 66
Step-by-step explanation:
QT is a midsegment. Thus, applying the midsegment theorem:
RS = 2(QT)
QT = z - 33,
RS = z
Plug in the values into the equation
z = 2(z - 33)
z = 2z - 66
Subtract 2z from each side
z - 2z = -66
-z = -66
Divide both sides by -1
z = 66
Answer:
44%
Step-by-step explanation:
100 + 20 = 120/100
(1.2)^2=1.44
144 - 100 = 44%
Answer:
4 and 8
Step-by-step explanation:
corresponding angles are two angles that have the same angle degree and are on the same side of the graph if you were to take the bottom part and move it up to the top part
Median is 19
IQR is 12
Range is 22
See photo below for explanation
