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alina1380 [7]
4 years ago
5

Suppose Aldo borrows $5500 at an interest rate of 9% compounded each year assume that no payments are made on the loan how much

money is owed at the end of one year and how much is over at the end of two years
Mathematics
1 answer:
ollegr [7]4 years ago
3 0
11,990

9% of 5500 is 495
(495+5500) [one year] x 2 [two years] = $11,990

At the end of 2 years, Aldo will owe $11,990.
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A ship is 5 miles east and 2 miles north away
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Step-by-step explanation:

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3 years ago
Find the equations of all lines tangent to y = 9–x^2 that pass through the point (1, 12). ...?
Oksanka [162]
The slope of the tangent at a given point can be found by differentiating the given equation and substituting the value of x at the point as such:
y = 9 - x²
dy/dx = -2x; x = 1
dy/dx = -2

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y -12 = -2(x - 1)
4 0
3 years ago
Use the information to solve the triangle. Round your answers to two decimal places. Hint: draw a sketch first to determine if y
Anestetic [448]

Answer:

A = 43°

b = 25.8 (3 sig. fig.)

c = 14.5 (3 sig. fig.)

Step-by-step explanation:

Using angle sum of triangle, we get A = 180 - 104 - 33 = 43°

Using sin law,

b/sin104 = 18.1/sin43

b = 25.8 (3 sig. fig.)

c/sin33 = 18.1/sin43

c = 14.5 (3 sig. fig.)

7 0
3 years ago
Which function has zeros at x=-2 and x=5
Natalka [10]

Answer:

y=2.5x+5 or f(x)=2.5x+5

Step-by-step explanation:

We know 2 given points. (-2, 0) and (0,5)

With these two points we can calculate the slope:

0-5/-2-0+

-5/-2=

5/2 = 2.5

Because the y-intercept is given at 5, we can put these numbers into y=mx+b and get y=2.5x+5 or f(x)=2.5x+5

6 0
3 years ago
How do you do x ^4-4? What is the x values?
VladimirAG [237]
We know that
A difference of two perfect squares (A² - B²)  <span>can be factored into </span><span> (A+B) • (A-B)
</span> then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2

the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2

i <span> is called the </span><span>imaginary unit. </span><span>It satisfies </span><span>  i</span>²<span>  =-1
</span><span>Both </span><span>  i </span><span>  and </span><span>  -i </span><span>  are the square roots of </span><span>  -1 
</span><span>√<span> -2 </span></span> =√<span> -1• 2  </span><span> = </span>√ -1 •√<span>  2  </span> =i • <span> √<span> 2 </span></span>
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3=  0 + √2<span> <span>i  
</span></span>x4=  0  - √2<span> i </span>

the answer is 

the values of x are
x1=+√2
x2=-√2
x3=  0 + √2 i  
x4=  0  - √2 i

3 0
3 years ago
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