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charle [14.2K]
2 years ago
6

Use a recursive function for the geometric sequence 2, -4, 8, -16 to represent the 9th term. brainly

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
5 0

Answer:

512

Step-by-step explanation:

(a)=a*r^( n − 1)

(9)=2*(-2)^( 9− 1)

   =512

hope this help

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Matilda is selling hand-painted vases at a craft fair. She will
sladkih [1.3K]

Answer:

14x>200+5.5, She must sell 15 or more vases

Step-by-step explanation:

14x>200+5.5

14x>200+5.5

14x>205.5

x>14.68*

She must sell 15 or more vases

*You round up because you cannot sell a partial vase

7 0
2 years ago
Find the length of the radius of a sphere with a surface area of 5541.77 cm2.
ladessa [460]
The area of a sphere: A  = 4.π.R²

A= 5541.77 → 5541.77 = 4.π.R²

R² = (5541.77)/(4.π)
R² = 441; → R =√441; R = 21 cm

6 0
3 years ago
prism x is showen below. the volume of prism y is 10 cubic cm greater than the volume of prism x. what is the volume of prism y.
Vlad1618 [11]

Answer:

it’s 3 x 2x 5 = 30

Then use that product and times it by 10. ( 10 x 30 )

Ans = 300 cubic centimeters

Step-by-step explanation:

3 x 5 x 2 = 30


30 x 10 = 300

Ans = 300 cubic centimeters

4 0
1 year ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
an elephant eats about 2500 pounds of food in 10 days. About how muck food does an elephant eat in 1000 days
andriy [413]
2500/10=250
250 represents how much the elephant can eat in one day. Since they want to know how much the elephant can eat in 1000 days you would multiply 250 and 1000 which leaves you with 250,000 pounds of food.

The elephant can eat 250,000 pounds of food in 10 days. :)
3 0
3 years ago
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