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andrezito [222]
3 years ago
11

Which point is a solution to the system below 2y<-12x+4 y<-6x+4?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer: All points in the shaded region after 2y<-12x+4 is the solution.

Step-by-step explanation:

Since we have given that

2y

We need to find the point of solution to the system of inequalities:

Suppose

2y=-12x+4\\and\\y=-6x+4

We first check the consistency of the system of equation:

\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{2}{1}=\frac{-12}{-6}=\frac{4}{4}\\\\2=2\neq 1

So, it is parallel system of equations, but we consider it as an inequality, so all the points in the shaded region is the solution.

Using zero test,

2y

0<4 it is true so, shaded part is towards the center.

Similarly,

y

0<4 again it is true it would be shaded towards the center.

So, the common part will be after 2y<-12x+4 .

Hence, all the points in the shaded region is the solution.

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Kay Sadia sold merchandise for $7,200 subject to 8% sales tax. The entry in the general journal to record the sale will include:
Mandarinka [93]
Answer:
The entry journal to record the sale will include a debit to accounts receivable for $7776

Explanation:
The original price of merchandise = $7200
The tax is 8%
This means that when recording, kay sadia has to record the total of the original price in addition to the tax.
This means that:
Total record = original price + subject tax
Total record = 7200 + 0.08(7200)
Total record = 7200 + 576
Total record = $7776

Hope this helps :)


7 0
3 years ago
What is the measurement of N?
zhuklara [117]

Answer:

D 141

Step-by-step explanation:

since it has to equal 180 just add each answer to the other number on the diagram so you answer us

39 + 141= 180

141

PLZ MARK ME BRAINLIEST

5 0
3 years ago
Heyy! i’ll give brainliest please help.
worty [1.4K]

Answer: the first one :-)

Step-by-step explanation:

7 0
3 years ago
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Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?
Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}


so we're really looking for a line whose slope is 3 and runs through (1,5)


\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2

4 0
3 years ago
Equivalent expression with fewer terms to -9x-3x+15+x-4
kykrilka [37]

Answer:

−11x+11

Step-by-step explanation:

3 0
4 years ago
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