<h3>Answers:</h3>
- (a) The function is increasing on the interval (0, infinity)
- (b) The function is decreasing on the interval (-infinity, 0)
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Explanation:
You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).
The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)
Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)
1.d. 2.c 3.b 4.d Justt got a 100% its right!!!
Answer:
A: f(x)=10cos(2π/5 x)+10
Step-by-step explanation:
The coefficient of x in the cosine argument of the function will be 2π/period. Since the period is 5, the coefficient is 2π/5. This observation eliminates choices B and C.
The description "not a reflection of the parent function over the x-axis" means the multiplier of the cosine function is not negative, eliminating choice D.
The remaining choice A matches the description.
Answer:
Step-by-step explanation:
Eliminating a negative and changing our operation
Rewriting our equation with parts separated
Solving the whole number parts
Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12
Combining the whole and fraction parts
[RevyBreeze]
<u>Answer:</u>
Cost of sand = £150
Cost of bricks = £157.5
Cost of cement = £134
Total cost = £441.50
<u>Step-by-step explanation:</u>
We are given that:
2 tonnes of sand is for £75.00 per tonne,
20 bags of cement are for £6.70 per bag,
350 bricks at 45p each,
So, 2 tonnes of sand at £75.00 per tonne = 2 * £75.00 = £150.00
20 bags of cement at £6.70 per bag = 20 * £6.70 = £134.00
350 bricks at 45p each = 350 * £0.45 = £157.50
Therefore, the total cost of all the materials = £150 + £134 + £157.5 = £441.50
