In the diagram, which angles are vertical angles? Select

En una sociedad participan 5 socios, colocando todos capitales iguales, lo unico que el primer socio estuvo 1 año y medio, el se

Mashutka [201]

Answer:

Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

Step-by-step explanation:

Dado que en una sociedad participan 5 socios, colocando todos capitales iguales, lo único que el primer socio estuvo 1 año y medio, el segundo 9 meses, el tercero 5 meses mas que el primero, el cuarto 1 año 7 meses y el quinto 2 años, para determinar cuánto le toca a cada socio de una utilidad de Q. 55,230.00 se deben realizar los siguientes cálculos:

Socio 1 = 1.5 años

Socio 2 = 0.75 años

Socio 3 = 1.916 años

Socio 4 = 1.583 años

Socio 5 = 2 años

Total = 1.5 + 0.75 + 1.916 + 1.583 + 2 = 7.75

Socio 1 =

7.75 = 100

1.50 = X

1.50 x 100 / 7.75 = X

19.35 = X

55,230 x 0.1935 = 10,690

Socio 2 =

7.75 = 100

0.75 = X

0.75 x 100 / 7.75 = X

9.68 = X

55,230 x 0.0968 = 5,345

Socio 3 =

7.75 = 100

1.916 = X

1.916 x 100 / 7.75 = X

24.72 = X

55,230 x 0.2472 = 13,655

Socio 4 =

7.75 = 100

1.583 = X

1.583 x 100 / 7.75 = X

20.43 = X

55,230 x 0.2043 = 11,285

Socio 5 =

7.75 = 100

2 = X

2 x 100 / 7.75 = X

25.81 = X

55,230 x 0.2581 = 14,255

Por lo tanto, Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

5 0

3 years ago

a packe of cards conatins 4 red and 5 black cards. a hand of 5 cards is drawn without replacment. What is the proablity of all f

Vladimir79 [104]

Answer: Our required probability is 0.3387.

Step-by-step explanation:

Since we have given that

Number of red cards = 4

Number of black cards = 5

Number of cards drawn = 5

We need to find the probability of getting exactly three black cards.

Probability of getting a black card = $\dfrac{5}{9}$

Probability of getting a red card = $\dfrac{4}{9}$

So, using "Binomial distribution", let X be the number of black cards:

$P(X=3)=^5C_3(\dfrac{5}{9})^3(\dfrac{4}{9})^2\\\\P(X=3)=0.3387$

Hence, our required probability is 0.3387.

5 0

3 years ago

-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

Original Equation :
$\frac{-3}{v} = -6$

New Equation {Added Multiply Both Sides by V} :
$\frac{-3}{v} v=-6v$

Solution {New Equation Solved} :
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

Old Equation :
$-3 = -6v$

New Equation {Switched} :
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

Old Equation :
$-6v = -3$

New Equation {Added Divide Both Sides by V} :
$\frac{-6v}{v} = \frac{-3}{v}$

Solution {New Equation Solved} :
$v = \frac{1}{2}$

So, this means that in the equation $\frac{-3}{v} =-6$ , $v = \frac{1}{2}$ .

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

70=(4x+36)/2 figure this out please

adell [148]

Answer:

$\boxed{\bold{\huge{\boxed{x = 26}}}}$