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4 years ago

Two decimal numbers have a difference of 0.7 And and a sum of 1.What are the numbers?

2 answers:

4 0

Use an equation for questions like these:
I'll use x and y as the unknown numbers
x-y=0.7
x+y=1
Just choose either x or y to solve for
y=x-0.7
y=-x+1
Then since since they're both equal to y then they can equal each other
x-0.7=-x+1
2x-0.7=1
2x=1.7
x=0.85
Then just grab one of the equations and use it to find y
0.85+y=1
y=0.15

So the two numbers are 0.85 and 0.15

klio [65]4 years ago

3 0

The two numbers are 0.85 and 0.15
if you add them together you get 1, 0.85+0.15=1
and if you subtract them you get 0.7, 0.85-0.15=0.7

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The table shows the profit and loss of the after -school snack stand write each profit as a positive number and each loss a nega

kiruha [24]

Answer:

Profit

7.50

4.50

Loss

-3.50

-6.00

Step-by-step explanation:

Here, we want to write each profit as a positive number and each loss as a negative number

thus, we have that;

Profit;

7.50

4.50

Loss;

-3.50

-6.00

7 0

3 years ago

PLEASE FAST 10 POINTS

Karolina [17]

Answer:

6. 5 % is the answer

Step-by-step explanation:

formula =

R = I × 100 / P × T

4 0

3 years ago

Listed below are the numbers of heroic firefighters who lost their lives in the United States each year while fighting forest fi

Marysya12 [62]

Answer:

Step-by-step explanation:

Hello!

Data

Year/Firefighters

2000: 20

2001: 18

2002: 23

2003: 30

2004: 20

2005: 12

2006: 24

2007: 9

2008: 25

2009: 15

2010: 8

2011: 11

2012: 15

2013: 34

Common measures of variation

Variance

S²= $\frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]$

∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34

∑X= 264

∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²

∑X²= 5770

n= 14

S²= $\frac{1}{13}[5770-\frac{(264)^2}{14} ]$

S²= 60.90

Standard deviation

The standard deviation is the square root of the variance

S= √S²= √60.90= 7.80

Coefficient of variation

Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.

C.V.= $\frac{S}{X[bar]}$ *100 = $\frac{7.80}{18.86}$ *100= 41.36%

The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.

X[bar]= ∑X/n= 264/14= 18.86

Range

In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.

R= Xmax - Xmin= 34 - 8= 26

Xmax= 34

Xmin= 8

Inter Quartile Range

Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.

IQR= C₃ - C₁= 23.5 - 11.5 = 12

Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.

Pos1: n/4= 14/4= 3.5

The first quantile is the number between position 3 and position 4

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₁= (11+12)/2= 11.5

Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.

Pos3: n*3/4= 14*3/4= 10.5

The third Quantile is between position 10 and 11

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₃= (23+24)/2= 23.5

The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.

I hope it helps!

6 0

3 years ago

What’s the slope of (-3,4)(2,-5)

olasank [31]

-9/5 or -1.8
2 - - 3 = 5
-5 - 4 = -9

6 0

3 years ago

Read 2 more answers

He unit circle has a radius of 1 unit and is centered at the origin. It is dilated so that it passes through the point (4, 0).

Advocard [28]

We know that

if the dilated circle passes through the point (4, 0)
so
the new radius is the distance from the origin to point (4,0)
d=√[(4-0)²+0²]-----> d=√16------> d=4 units

the new radius is 4 units
original radius is 1 units

[new radius]=[scale]*[original radius]
scale=new radius/original radius-----> scale=4/1-----> 4

the answer is
the scale factor of dilation is 4

5 0

4 years ago