To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas 2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol
It's 2) a positively-charged nucleus is surrounded by mostly empty space (aka Rutherford's Model).
Most of the atom's mass is inside the nucleus (which contains protons [+] and neutrons [0 charge]), while the electrons [-] "float" around the nucleus like clouds. This is why it's said that the atom is 'mostly empty space'.
Mghcl14 + H2 = mghclh 16 work needed to solve this problem
Answer:
I think its true I dont really know
Explanation:
true
Answer:
See the figure
Explanation:
In this case, we have to take into account the <u>stability of the carbocations</u>:
Terciary>Secundary>>Primary.
In other words, is we have the <u>most substituted carbocation</u> we will have more stability. Therefore in the carbocation formation, the charge would go in the <u>most substituted carbon</u> of the double bond for each case.
