x=1, y=2
Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3
5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3
In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3
Add 20 to both sides:{y = 5 - 3 x17 x = 17
Divide both sides by 17:{y = 5 - 3 xx = 1
Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer: {x = 1 y = 2
The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2
Answer:
yes
Step-by-step explanation:
