Question

Priya's cat is pregnant with a litter of 5 kittens. Each kitten had a 30% chance of being chocolate brown. Estimate the probability that exactly 2 kittens will be chocolate brown.

Answer 1

Answer:

So, the probability is P=0.3087.

Step-by-step explanation:

We know that Priya's cat is pregnant with a litter of 5 kittens, so n=5.

Each kitten had a 30% chance of being chocolate brown.  

We get that p=0.3 and q=1-0.3=0.7.

We calculate the probability that exactly 2 kittens will be chocolate brown, so k=2.

We use the formula:

$\boxed{P(X=k)=C_k^n\cdot p^k\cdot q^{n-k}}$

we get

$P(X=2)=C_2^5\cdot 0.3^2\cdot 0.7^3\\\\P(X=2)=\frac{5!}{2!(5-2)!}\cdot 0.03087\\\\P(X=2)=10\cdot 0.03087\\\\P(X=2)=0.3087$

So, the probability is P=0.3087.