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VladimirAG [237]
4 years ago
15

Priya's cat is pregnant with a litter of 5 kittens. Each kitten had a 30% chance of being chocolate brown. Estimate the probabil

ity that exactly 2 kittens will be chocolate brown.
Mathematics
1 answer:
aniked [119]4 years ago
5 0

Answer:

So, the probability is P=0.3087.

Step-by-step explanation:

We know that Priya's cat is pregnant with a litter of 5 kittens, so n=5.

Each kitten had a 30% chance of being chocolate brown.  

We get that p=0.3 and q=1-0.3=0.7.

We calculate the probability that exactly 2 kittens will be chocolate brown, so k=2.

We use the formula:

\boxed{P(X=k)=C_k^n\cdot p^k\cdot q^{n-k}}

we get

P(X=2)=C_2^5\cdot 0.3^2\cdot 0.7^3\\\\P(X=2)=\frac{5!}{2!(5-2)!}\cdot 0.03087\\\\P(X=2)=10\cdot 0.03087\\\\P(X=2)=0.3087\\

So, the probability is P=0.3087.

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