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bija089 [108]
3 years ago
13

10 seconds into a race, Clara was at the 25 meter mark. At 60 seconds into the race, she was at the 100 meter mark. What was the

approximate rate of change in Clara's speed between 10 seconds and 60 seconds?
Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

1.5 m/s

Step-by-step explanation:

To find the rate of change for two different sets of data, you have to divide the distance and the time to find the speed.  

Using the general formula: d = rt, where d=distance, r=rate and t=time,

r = d/t

\frac{distance}{time}=\frac{meters}{second}=\frac{75}{50}=1.5m/s

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3 years ago
The difference of two numbers is 16 and the sum of their squares is 130. What are the numbers.
Korvikt [17]
x - y = 16
x^2 + x^2 = 130

----------------
x^2 - y^2 = 256
+(x^2 + y^2 = 130)
2x^2 = 386
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x = <span>13.892 (3DP)
----
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The numbers are: 13.892 and -2.108
4 0
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