Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Answer:
672
Step-by-step explanation:
Formula is length times width times height
14 x 8 = 112
112 x 6 = 672
The ratio is 2:3 for the side lengths of the triangles.
so 6:9 is one side and 5:x would be the other side
2/3 of five is 3.33 and multiplying that by 2 gives you 6.67
Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (normal)
∠A=∠A (Given)
BA=CD (Sides inverse to rise to points are consistently equivalent)
With the SAS rule of congruency,
ΔABD≅ΔDCA
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